Search a number
-
+
13310032223333 is a prime number
BaseRepresentation
bin1100000110101111101110…
…1111100001110001100101
31202010102112000211022020202
43001223323233201301211
53221032421222121313
644150313331040245
72542422002124416
oct301537357416145
952112460738222
1013310032223333
11427183121a95a
1215ab6a6a40085
13757191077441
143402cd6b780d
1518135796b558
hexc1afbbe1c65

13310032223333 has 2 divisors, whose sum is σ = 13310032223334. Its totient is φ = 13310032223332.

The previous prime is 13310032223311. The next prime is 13310032223351. The reversal of 13310032223333 is 33332223001331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8432855907844 + 4877176315489 = 2903938^2 + 2208433^2 .

It is a cyclic number.

It is not a de Polignac number, because 13310032223333 - 234 = 13292852354149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13310032223296 and 13310032223305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310032223833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655016111666 + 6655016111667.

It is an arithmetic number, because the mean of its divisors is an integer number (6655016111667).

Almost surely, 213310032223333 is an apocalyptic number.

It is an amenable number.

13310032223333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310032223333 is an equidigital number, since it uses as much as digits as its factorization.

13310032223333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 29.

Adding to 13310032223333 its reverse (33332223001331), we get a palindrome (46642255224664).

The spelling of 13310032223333 in words is "thirteen trillion, three hundred ten billion, thirty-two million, two hundred twenty-three thousand, three hundred thirty-three".