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13310131203331 is a prime number
BaseRepresentation
bin1100000110110000000110…
…1001000110110100000011
31202010102202221002000021121
43001230001221012310003
53221033122042001311
644150331224333111
72542424313341014
oct301540151066403
952112687060247
1013310131203331
114271882085006
1215ab714014197
137571a87218a1
143402dc8c100b
151813614bdb71
hexc1b01a46d03

13310131203331 has 2 divisors, whose sum is σ = 13310131203332. Its totient is φ = 13310131203330.

The previous prime is 13310131203293. The next prime is 13310131203349. The reversal of 13310131203331 is 13330213101331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13310131203331 - 213 = 13310131195139 is a prime.

It is a super-2 number, since 2×133101312033312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13310131203296 and 13310131203305.

It is not a weakly prime, because it can be changed into another prime (13310131203631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655065601665 + 6655065601666.

It is an arithmetic number, because the mean of its divisors is an integer number (6655065601666).

Almost surely, 213310131203331 is an apocalyptic number.

13310131203331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310131203331 is an equidigital number, since it uses as much as digits as its factorization.

13310131203331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13310131203331 its reverse (13330213101331), we get a palindrome (26640344304662).

The spelling of 13310131203331 in words is "thirteen trillion, three hundred ten billion, one hundred thirty-one million, two hundred three thousand, three hundred thirty-one".