Base | Representation |
---|---|
bin | 1100000110110000101111… |
… | …0000111000010001110111 |
3 | 1202010110012202121020111201 |
4 | 3001230023300320101313 |
5 | 3221033444024404421 |
6 | 44150400132113331 |
7 | 2542431444605164 |
oct | 301541360702167 |
9 | 52113182536451 |
10 | 13310301013111 |
11 | 4271959a17673 |
12 | 15ab760a65847 |
13 | 75720496844b |
14 | 34031728506b |
15 | 181371362b91 |
hex | c1b0bc38477 |
13310301013111 has 2 divisors, whose sum is σ = 13310301013112. Its totient is φ = 13310301013110.
The previous prime is 13310301013099. The next prime is 13310301013151. The reversal of 13310301013111 is 11131010301331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13310301013111 - 227 = 13310166795383 is a prime.
It is a super-3 number, since 3×133103010131113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310301013151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655150506555 + 6655150506556.
It is an arithmetic number, because the mean of its divisors is an integer number (6655150506556).
Almost surely, 213310301013111 is an apocalyptic number.
13310301013111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310301013111 is an equidigital number, since it uses as much as digits as its factorization.
13310301013111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 13310301013111 its reverse (11131010301331), we get a palindrome (24441311314442).
The spelling of 13310301013111 in words is "thirteen trillion, three hundred ten billion, three hundred one million, thirteen thousand, one hundred eleven".
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