Base | Representation |
---|---|
bin | 11000110010101101… |
… | …10001100011010001 |
3 | 1021100121200102100121 |
4 | 30121112301203101 |
5 | 204224414134132 |
6 | 10040433550241 |
7 | 650561463256 |
oct | 143126614321 |
9 | 37317612317 |
10 | 13310302417 |
11 | 5710356235 |
12 | 26b5715381 |
13 | 1341768bb9 |
14 | 903a6142d |
15 | 52d7e8497 |
hex | 3195b18d1 |
13310302417 has 2 divisors, whose sum is σ = 13310302418. Its totient is φ = 13310302416.
The previous prime is 13310302403. The next prime is 13310302487. The reversal of 13310302417 is 71420301331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9936899856 + 3373402561 = 99684^2 + 58081^2 .
It is an emirp because it is prime and its reverse (71420301331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13310302417 - 215 = 13310269649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13310302391 and 13310302400.
It is not a weakly prime, because it can be changed into another prime (13310302487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655151208 + 6655151209.
It is an arithmetic number, because the mean of its divisors is an integer number (6655151209).
Almost surely, 213310302417 is an apocalyptic number.
It is an amenable number.
13310302417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310302417 is an equidigital number, since it uses as much as digits as its factorization.
13310302417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13310302417 its reverse (71420301331), we get a palindrome (84730603748).
The spelling of 13310302417 in words is "thirteen billion, three hundred ten million, three hundred two thousand, four hundred seventeen".
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