13310312141047 has 2 divisors, whose sum is σ = 13310312141048. Its totient is φ = 13310312141046.

The previous prime is 13310312140987. The next prime is 13310312141057. The reversal of 13310312141047 is 74014121301331.

13310312141047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13310312141047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310312141057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655156070523 + 6655156070524.

It is an arithmetic number, because the mean of its divisors is an integer number (6655156070524).

Almost surely, 2^{13310312141047} is an apocalyptic number.

13310312141047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310312141047 is an equidigital number, since it uses as much as digits as its factorization.

13310312141047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 13310312141047 its reverse (74014121301331), we get a palindrome (87324433442378).

The spelling of 13310312141047 in words is "thirteen trillion, three hundred ten billion, three hundred twelve million, one hundred forty-one thousand, forty-seven".