Search a number
-
+
13310312300 = 2252133103123
BaseRepresentation
bin11000110010101101…
…10011111101101100
31021100121200220220122
430121112303331230
5204224414443200
610040434104112
7650561534135
oct143126637554
937317626818
1013310312300
1157103626aa
1226b571b038
13134177054c
14903a64c8c
1552d7eb385
hex3195b3f6c

13310312300 has 18 divisors (see below), whose sum is σ = 28883377908. Its totient is φ = 5324124880.

The previous prime is 13310312293. The next prime is 13310312311. The reversal of 13310312300 is 321301331.

It is a super-3 number, since 3×133103123003 (a number of 31 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 66551462 + ... + 66551661.

It is an arithmetic number, because the mean of its divisors is an integer number (1604632106).

Almost surely, 213310312300 is an apocalyptic number.

13310312300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13310312300 is an abundant number, since it is smaller than the sum of its proper divisors (15573065608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13310312300 is a wasteful number, since it uses less digits than its factorization.

13310312300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 133103137 (or 133103130 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13310312300 its reverse (321301331), we get a palindrome (13631613631).

It can be divided in two parts, 1331031 and 2300, that added together give a palindrome (1333331).

The spelling of 13310312300 in words is "thirteen billion, three hundred ten million, three hundred twelve thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 133103123 266206246 532412492 665515615 1331031230 2662062460 3327578075 6655156150 13310312300