Base | Representation |
---|---|
bin | 1100000110110000110011… |
… | …1010111101110010111001 |
3 | 1202010110021010010221110021 |
4 | 3001230030322331302321 |
5 | 3221034014012344421 |
6 | 44150402104250441 |
7 | 2542432101643666 |
oct | 301541472756271 |
9 | 52113233127407 |
10 | 13310320434361 |
11 | 4271969982095 |
12 | 15ab767470a21 |
13 | 7572089a8302 |
14 | 340319a9ca6d |
15 | 181372dec341 |
hex | c1b0cebdcb9 |
13310320434361 has 2 divisors, whose sum is σ = 13310320434362. Its totient is φ = 13310320434360.
The previous prime is 13310320434337. The next prime is 13310320434409. The reversal of 13310320434361 is 16343402301331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9582466949136 + 3727853485225 = 3095556^2 + 1930765^2 .
It is a cyclic number.
It is not a de Polignac number, because 13310320434361 - 29 = 13310320433849 is a prime.
It is not a weakly prime, because it can be changed into another prime (13310320434161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655160217180 + 6655160217181.
It is an arithmetic number, because the mean of its divisors is an integer number (6655160217181).
Almost surely, 213310320434361 is an apocalyptic number.
It is an amenable number.
13310320434361 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310320434361 is an equidigital number, since it uses as much as digits as its factorization.
13310320434361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 34.
Adding to 13310320434361 its reverse (16343402301331), we get a palindrome (29653722735692).
The spelling of 13310320434361 in words is "thirteen trillion, three hundred ten billion, three hundred twenty million, four hundred thirty-four thousand, three hundred sixty-one".
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