Base | Representation |
---|---|
bin | 1100000110110000110110… |
… | …0100011101010000000111 |
3 | 1202010110021212121112112212 |
4 | 3001230031210131100013 |
5 | 3221034024303423421 |
6 | 44150403133334035 |
7 | 2542432263254432 |
oct | 301541544352007 |
9 | 52113255545485 |
10 | 13310331311111 |
11 | 4271975030a3a |
12 | 15ab76b03731b |
13 | 75720b015c63 |
14 | 34031b2d0819 |
15 | 181373d49e5b |
hex | c1b0d91d407 |
13310331311111 has 2 divisors, whose sum is σ = 13310331311112. Its totient is φ = 13310331311110.
The previous prime is 13310331311093. The next prime is 13310331311149. The reversal of 13310331311111 is 11111313301331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13310331311111 is a prime.
It is a super-2 number, since 2×133103313111112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310331911111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655165655555 + 6655165655556.
It is an arithmetic number, because the mean of its divisors is an integer number (6655165655556).
Almost surely, 213310331311111 is an apocalyptic number.
13310331311111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310331311111 is an equidigital number, since it uses as much as digits as its factorization.
13310331311111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 23.
Adding to 13310331311111 its reverse (11111313301331), we get a palindrome (24421644612442).
The spelling of 13310331311111 in words is "thirteen trillion, three hundred ten billion, three hundred thirty-one million, three hundred eleven thousand, one hundred eleven".
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