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13310331311111 is a prime number
BaseRepresentation
bin1100000110110000110110…
…0100011101010000000111
31202010110021212121112112212
43001230031210131100013
53221034024303423421
644150403133334035
72542432263254432
oct301541544352007
952113255545485
1013310331311111
114271975030a3a
1215ab76b03731b
1375720b015c63
1434031b2d0819
15181373d49e5b
hexc1b0d91d407

13310331311111 has 2 divisors, whose sum is σ = 13310331311112. Its totient is φ = 13310331311110.

The previous prime is 13310331311093. The next prime is 13310331311149. The reversal of 13310331311111 is 11111313301331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13310331311111 is a prime.

It is a super-2 number, since 2×133103313111112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310331911111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655165655555 + 6655165655556.

It is an arithmetic number, because the mean of its divisors is an integer number (6655165655556).

Almost surely, 213310331311111 is an apocalyptic number.

13310331311111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310331311111 is an equidigital number, since it uses as much as digits as its factorization.

13310331311111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 23.

Adding to 13310331311111 its reverse (11111313301331), we get a palindrome (24421644612442).

The spelling of 13310331311111 in words is "thirteen trillion, three hundred ten billion, three hundred thirty-one million, three hundred eleven thousand, one hundred eleven".