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1331089266373 is a prime number
BaseRepresentation
bin10011010111101011000…
…110100101011011000101
311201020202220021211011021
4103113223012211123011
5133302032323010443
62455254410311141
7165111430040056
oct23275306453305
94636686254137
101331089266373
1147356a20a169
12195b831284b1
13986a1052749
14485d453a72d
15249584b49ed
hex135eb1a56c5

1331089266373 has 2 divisors, whose sum is σ = 1331089266374. Its totient is φ = 1331089266372.

The previous prime is 1331089266359. The next prime is 1331089266379. The reversal of 1331089266373 is 3736629801331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1289694108609 + 41395157764 = 1135647^2 + 203458^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331089266373 - 217 = 1331089135301 is a prime.

It is a super-2 number, since 2×13310892663732 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1331089266373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331089266379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665544633186 + 665544633187.

It is an arithmetic number, because the mean of its divisors is an integer number (665544633187).

Almost surely, 21331089266373 is an apocalyptic number.

It is an amenable number.

1331089266373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331089266373 is an equidigital number, since it uses as much as digits as its factorization.

1331089266373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2939328, while the sum is 52.

The spelling of 1331089266373 in words is "one trillion, three hundred thirty-one billion, eighty-nine million, two hundred sixty-six thousand, three hundred seventy-three".