13311041252513 has 2 divisors, whose sum is σ = 13311041252514. Its totient is φ = 13311041252512.

The previous prime is 13311041252501. The next prime is 13311041252519. The reversal of 13311041252513 is 31525214011331.

13311041252513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7235545870609 + 6075495381904 = 2689897^2 + 2464852^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311041252513 - 2¹⁰ = 13311041251489 is a prime.

It is a super-2 number, since 2×13311041252513² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13311041252513.

It is not a weakly prime, because it can be changed into another prime (13311041252519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655520626256 + 6655520626257.

It is an arithmetic number, because the mean of its divisors is an integer number (6655520626257).

Almost surely, 2^{13311041252513} is an apocalyptic number.

It is an amenable number.

13311041252513 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311041252513 is an equidigital number, since it uses as much as digits as its factorization.

13311041252513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 13311041252513 its reverse (31525214011331), we get a palindrome (44836255263844).

The spelling of 13311041252513 in words is "thirteen trillion, three hundred eleven billion, forty-one million, two hundred fifty-two thousand, five hundred thirteen".