Base | Representation |
---|---|
bin | 1100000110110011101101… |
… | …1101101111100011101111 |
3 | 1202010112021112111011212211 |
4 | 3001230323131233203233 |
5 | 3221042113413144043 |
6 | 44151011401111251 |
7 | 2542460333140006 |
oct | 301547335574357 |
9 | 52115245434784 |
10 | 13311101303023 |
11 | 427222a736297 |
12 | 15ab944a88527 |
13 | 7573016c0284 |
14 | 340391687c3d |
15 | 1813bb745a9d |
hex | c1b3b76f8ef |
13311101303023 has 2 divisors, whose sum is σ = 13311101303024. Its totient is φ = 13311101303022.
The previous prime is 13311101302997. The next prime is 13311101303057. The reversal of 13311101303023 is 32030310111331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13311101303023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13311101302985 and 13311101303003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13311101300023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655550651511 + 6655550651512.
It is an arithmetic number, because the mean of its divisors is an integer number (6655550651512).
Almost surely, 213311101303023 is an apocalyptic number.
13311101303023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311101303023 is an equidigital number, since it uses as much as digits as its factorization.
13311101303023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 13311101303023 its reverse (32030310111331), we get a palindrome (45341411414354).
The spelling of 13311101303023 in words is "thirteen trillion, three hundred eleven billion, one hundred one million, three hundred three thousand, twenty-three".
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