13311110120232 has 64 divisors (see below), whose sum is σ = 33378220800000. Its totient is φ = 4423663934144.

The previous prime is 13311110120179. The next prime is 13311110120263. The reversal of 13311110120232 is 23202101111331.

It is a junction number, because it is equal to n+sod(n) for n = 13311110120199 and 13311110120208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10058269 + ... + 11304467.

It is an arithmetic number, because the mean of its divisors is an integer number (521534700000).

Almost surely, 2^{13311110120232} is an apocalyptic number.

13311110120232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13311110120232 is an abundant number, since it is smaller than the sum of its proper divisors (20067110679768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311110120232 is a wasteful number, since it uses less digits than its factorization.

13311110120232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247550 (or 1247546 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13311110120232 its reverse (23202101111331), we get a palindrome (36513211231563).

The spelling of 13311110120232 in words is "thirteen trillion, three hundred eleven billion, one hundred ten million, one hundred twenty thousand, two hundred thirty-two".