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133111112230 = 2513311111223
BaseRepresentation
bin111101111111000001…
…0100110001000100110
3110201120202001010021201
41323332002212020212
54140102421042410
6141052253033114
712421421533255
oct1737602461046
9421522033251
10133111112230
11514a7830868
122196a78579a
13c7245c0745
14662a75679c
1536e105483a
hex1efe0a6226

133111112230 has 8 divisors (see below), whose sum is σ = 239600002032. Its totient is φ = 53244444888.

The previous prime is 133111112159. The next prime is 133111112243. The reversal of 133111112230 is 32211111331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 133111112198 and 133111112207.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6655555602 + ... + 6655555621.

It is an arithmetic number, because the mean of its divisors is an integer number (29950000254).

Almost surely, 2133111112230 is an apocalyptic number.

133111112230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133111112230 is a deficient number, since it is larger than the sum of its proper divisors (106488889802).

133111112230 is a wasteful number, since it uses less digits than its factorization.

133111112230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13311111230.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 133111112230 its reverse (32211111331), we get a palindrome (165322223561).

The spelling of 133111112230 in words is "one hundred thirty-three billion, one hundred eleven million, one hundred twelve thousand, two hundred thirty".

Divisors: 1 2 5 10 13311111223 26622222446 66555556115 133111112230