1331113412113 has 2 divisors, whose sum is σ = 1331113412114. Its totient is φ = 1331113412112.

The previous prime is 1331113412093. The next prime is 1331113412131. The reversal of 1331113412113 is 3112143111331.

Together with next prime (1331113412131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1250677645569 + 80435766544 = 1118337^2 + 283612^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331113412113 - 2⁵ = 1331113412081 is a prime.

It is a super-2 number, since 2×1331113412113² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1331113412143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665556706056 + 665556706057.

It is an arithmetic number, because the mean of its divisors is an integer number (665556706057).

Almost surely, 2^{1331113412113} is an apocalyptic number.

It is an amenable number.

1331113412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331113412113 is an equidigital number, since it uses as much as digits as its factorization.

1331113412113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 25.

Adding to 1331113412113 its reverse (3112143111331), we get a palindrome (4443256523444).

The spelling of 1331113412113 in words is "one trillion, three hundred thirty-one billion, one hundred thirteen million, four hundred twelve thousand, one hundred thirteen".