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13311140303134 = 26655570151567
BaseRepresentation
bin1100000110110011110111…
…0010100001000100011110
31202010112101020212120222101
43001230331302201010132
53221042203404200014
644151015313035314
72542461315501652
oct301547562410436
952115336776871
1013311140303134
11427224a753693
1215ab955b55b3a
137573097c696b
1434039691aa62
151813bed9b474
hexc1b3dca111e

13311140303134 has 4 divisors (see below), whose sum is σ = 19966710454704. Its totient is φ = 6655570151566.

The previous prime is 13311140303129. The next prime is 13311140303147. The reversal of 13311140303134 is 43130304111331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×133111403031343 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327785075782 + ... + 3327785075785.

It is an arithmetic number, because the mean of its divisors is an integer number (4991677613676).

Almost surely, 213311140303134 is an apocalyptic number.

13311140303134 is a deficient number, since it is larger than the sum of its proper divisors (6655570151570).

13311140303134 is an equidigital number, since it uses as much as digits as its factorization.

13311140303134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655570151569.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 13311140303134 its reverse (43130304111331), we get a palindrome (56441444414465).

The spelling of 13311140303134 in words is "thirteen trillion, three hundred eleven billion, one hundred forty million, three hundred three thousand, one hundred thirty-four".

Divisors: 1 2 6655570151567 13311140303134