Base | Representation |
---|---|
bin | 10011010111101100111… |
… | …011111101001000110001 |
3 | 11201020212001011222220002 |
4 | 103113230323331020301 |
5 | 133302113212044403 |
6 | 2455301425555345 |
7 | 165112252414454 |
oct | 23275473751061 |
9 | 4636761158802 |
10 | 1331120034353 |
11 | 47358561464a |
12 | 195b914a5b55 |
13 | 986a7536155 |
14 | 485d866949b |
15 | 2495b041188 |
hex | 135ecefd231 |
1331120034353 has 2 divisors, whose sum is σ = 1331120034354. Its totient is φ = 1331120034352.
The previous prime is 1331120034329. The next prime is 1331120034451. The reversal of 1331120034353 is 3534300211331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1037499104929 + 293620929424 = 1018577^2 + 541868^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331120034353 - 26 = 1331120034289 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331120034253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665560017176 + 665560017177.
It is an arithmetic number, because the mean of its divisors is an integer number (665560017177).
Almost surely, 21331120034353 is an apocalyptic number.
It is an amenable number.
1331120034353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331120034353 is an equidigital number, since it uses as much as digits as its factorization.
1331120034353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 1331120034353 its reverse (3534300211331), we get a palindrome (4865420245684).
The spelling of 1331120034353 in words is "one trillion, three hundred thirty-one billion, one hundred twenty million, thirty-four thousand, three hundred fifty-three".
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