Base | Representation |
---|---|
bin | 10011010111101100111… |
… | …011111101000111001101 |
3 | 11201020212001011222202101 |
4 | 103113230323331013031 |
5 | 133302113212044003 |
6 | 2455301425555101 |
7 | 165112252414252 |
oct | 23275473750715 |
9 | 4636761158671 |
10 | 1331120034253 |
11 | 473585614569 |
12 | 195b914a5a91 |
13 | 986a75360a9 |
14 | 485d8669429 |
15 | 2495b04111d |
hex | 135ecefd1cd |
1331120034253 has 2 divisors, whose sum is σ = 1331120034254. Its totient is φ = 1331120034252.
The previous prime is 1331120034161. The next prime is 1331120034289. The reversal of 1331120034253 is 3524300211331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 766678862404 + 564441171849 = 875602^2 + 751293^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331120034253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331120034353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665560017126 + 665560017127.
It is an arithmetic number, because the mean of its divisors is an integer number (665560017127).
Almost surely, 21331120034253 is an apocalyptic number.
It is an amenable number.
1331120034253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331120034253 is an equidigital number, since it uses as much as digits as its factorization.
1331120034253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 1331120034253 its reverse (3524300211331), we get a palindrome (4855420245584).
The spelling of 1331120034253 in words is "one trillion, three hundred thirty-one billion, one hundred twenty million, thirty-four thousand, two hundred fifty-three".
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