Base | Representation |
---|---|
bin | 10011010111101101000… |
… | …000111100101011011001 |
3 | 11201020212010122111021122 |
4 | 103113231000330223121 |
5 | 133302114030440233 |
6 | 2455301514015025 |
7 | 165112266505355 |
oct | 23275500745331 |
9 | 4636763574248 |
10 | 1331121343193 |
11 | 473586328a34 |
12 | 195b91a17475 |
13 | 986a78a3b05 |
14 | 485d88ca465 |
15 | 2495b1edd98 |
hex | 135ed03cad9 |
1331121343193 has 2 divisors, whose sum is σ = 1331121343194. Its totient is φ = 1331121343192.
The previous prime is 1331121343187. The next prime is 1331121343247. The reversal of 1331121343193 is 3913431211331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 717761395264 + 613359947929 = 847208^2 + 783173^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331121343193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331121343133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665560671596 + 665560671597.
It is an arithmetic number, because the mean of its divisors is an integer number (665560671597).
Almost surely, 21331121343193 is an apocalyptic number.
It is an amenable number.
1331121343193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331121343193 is an equidigital number, since it uses as much as digits as its factorization.
1331121343193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17496, while the sum is 35.
The spelling of 1331121343193 in words is "one trillion, three hundred thirty-one billion, one hundred twenty-one million, three hundred forty-three thousand, one hundred ninety-three".
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