Base | Representation |
---|---|
bin | 10011010111101101000… |
… | …000111100101100001111 |
3 | 11201020212010122111100122 |
4 | 103113231000330230033 |
5 | 133302114030440442 |
6 | 2455301514015155 |
7 | 165112266505463 |
oct | 23275500745417 |
9 | 4636763574318 |
10 | 1331121343247 |
11 | 473586328a83 |
12 | 195b91a174bb |
13 | 986a78a3b47 |
14 | 485d88ca4a3 |
15 | 2495b1eddd2 |
hex | 135ed03cb0f |
1331121343247 has 2 divisors, whose sum is σ = 1331121343248. Its totient is φ = 1331121343246.
The previous prime is 1331121343193. The next prime is 1331121343259. The reversal of 1331121343247 is 7423431211331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331121343247 - 212 = 1331121339151 is a prime.
It is a super-3 number, since 3×13311213432473 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331121348247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665560671623 + 665560671624.
It is an arithmetic number, because the mean of its divisors is an integer number (665560671624).
Almost surely, 21331121343247 is an apocalyptic number.
1331121343247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331121343247 is an equidigital number, since it uses as much as digits as its factorization.
1331121343247 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36288, while the sum is 35.
Adding to 1331121343247 its reverse (7423431211331), we get a palindrome (8754552554578).
The spelling of 1331121343247 in words is "one trillion, three hundred thirty-one billion, one hundred twenty-one million, three hundred forty-three thousand, two hundred forty-seven".
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