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133112200104959 is a prime number
BaseRepresentation
bin11110010001000010011001…
…011001110000101111111111
3122110022101212002120110012212
4132101002121121300233333
5114421402241211324314
61151034522303051035
740016016260133305
oct3621023131605777
9573271762513185
10133112200104959
1139460626805479
1212b1a0525a0a7b
13593757134c32a
1424c2944542275
15105c849122e3e
hex791099670bff

133112200104959 has 2 divisors, whose sum is σ = 133112200104960. Its totient is φ = 133112200104958.

The previous prime is 133112200104953. The next prime is 133112200105009. The reversal of 133112200104959 is 959401002211331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133112200104959 is a prime.

It is a super-3 number, since 3×1331122001049593 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133112200104953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556100052479 + 66556100052480.

It is an arithmetic number, because the mean of its divisors is an integer number (66556100052480).

Almost surely, 2133112200104959 is an apocalyptic number.

133112200104959 is a deficient number, since it is larger than the sum of its proper divisors (1).

133112200104959 is an equidigital number, since it uses as much as digits as its factorization.

133112200104959 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 41.

The spelling of 133112200104959 in words is "one hundred thirty-three trillion, one hundred twelve billion, two hundred million, one hundred four thousand, nine hundred fifty-nine".