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13311232220047 is a prime number
BaseRepresentation
bin1100000110110100001101…
…0001001001101110001111
31202010112121122211110021111
43001231003101021232033
53221042400422020142
644151032355112451
72542463513000206
oct301550321115617
952115548743244
1013311232220047
114272297624183
1215ab9808a2727
1375732286a278
143403a4c0623d
151813c7ea5e17
hexc1b43449b8f

13311232220047 has 2 divisors, whose sum is σ = 13311232220048. Its totient is φ = 13311232220046.

The previous prime is 13311232219991. The next prime is 13311232220089. The reversal of 13311232220047 is 74002223211331.

It is a strong prime.

It is an emirp because it is prime and its reverse (74002223211331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13311232220047 - 223 = 13311223831439 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311232820047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655616110023 + 6655616110024.

It is an arithmetic number, because the mean of its divisors is an integer number (6655616110024).

Almost surely, 213311232220047 is an apocalyptic number.

13311232220047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311232220047 is an equidigital number, since it uses as much as digits as its factorization.

13311232220047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 13311232220047 its reverse (74002223211331), we get a palindrome (87313455431378).

The spelling of 13311232220047 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty-two million, two hundred twenty thousand, forty-seven".