Base | Representation |
---|---|
bin | 11110010001000011001111… |
… | …001110000100110111101011 |
3 | 122110022111012000112211212201 |
4 | 132101003033032010313223 |
5 | 114421411113332330212 |
6 | 1151035152035321031 |
7 | 40016050532535316 |
oct | 3621031716046753 |
9 | 573274160484781 |
10 | 133113103011307 |
11 | 39460a4a442371 |
12 | 12b1a264a50177 |
13 | 5937686422843 |
14 | 24c29cc41797d |
15 | 105c89d525b57 |
hex | 7910cf384deb |
133113103011307 has 2 divisors, whose sum is σ = 133113103011308. Its totient is φ = 133113103011306.
The previous prime is 133113103011233. The next prime is 133113103011379. The reversal of 133113103011307 is 703110301311331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133113103011307 is a prime.
It is a super-2 number, since 2×1331131030113072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133113103011407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556551505653 + 66556551505654.
It is an arithmetic number, because the mean of its divisors is an integer number (66556551505654).
Almost surely, 2133113103011307 is an apocalyptic number.
133113103011307 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113103011307 is an equidigital number, since it uses as much as digits as its factorization.
133113103011307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1701, while the sum is 28.
Adding to 133113103011307 its reverse (703110301311331), we get a palindrome (836223404322638).
The spelling of 133113103011307 in words is "one hundred thirty-three trillion, one hundred thirteen billion, one hundred three million, eleven thousand, three hundred seven".
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