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133113103011307 is a prime number
BaseRepresentation
bin11110010001000011001111…
…001110000100110111101011
3122110022111012000112211212201
4132101003033032010313223
5114421411113332330212
61151035152035321031
740016050532535316
oct3621031716046753
9573274160484781
10133113103011307
1139460a4a442371
1212b1a264a50177
135937686422843
1424c29cc41797d
15105c89d525b57
hex7910cf384deb

133113103011307 has 2 divisors, whose sum is σ = 133113103011308. Its totient is φ = 133113103011306.

The previous prime is 133113103011233. The next prime is 133113103011379. The reversal of 133113103011307 is 703110301311331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133113103011307 is a prime.

It is a super-2 number, since 2×1331131030113072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133113103011407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556551505653 + 66556551505654.

It is an arithmetic number, because the mean of its divisors is an integer number (66556551505654).

Almost surely, 2133113103011307 is an apocalyptic number.

133113103011307 is a deficient number, since it is larger than the sum of its proper divisors (1).

133113103011307 is an equidigital number, since it uses as much as digits as its factorization.

133113103011307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1701, while the sum is 28.

Adding to 133113103011307 its reverse (703110301311331), we get a palindrome (836223404322638).

The spelling of 133113103011307 in words is "one hundred thirty-three trillion, one hundred thirteen billion, one hundred three million, eleven thousand, three hundred seven".