Search a number
-
+
133113103012031 is a prime number
BaseRepresentation
bin11110010001000011001111…
…001110000101000010111111
3122110022111012000112212212112
4132101003033032011002333
5114421411113332341111
61151035152035324235
740016050532540402
oct3621031716050277
9573274160485775
10133113103012031
1139460a4a44296a
1212b1a264a5067b
135937686422c7c
1424c29cc417d39
15105c89d525e8b
hex7910cf3850bf

133113103012031 has 2 divisors, whose sum is σ = 133113103012032. Its totient is φ = 133113103012030.

The previous prime is 133113103011991. The next prime is 133113103012037. The reversal of 133113103012031 is 130210301311331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133113103012031 - 214 = 133113102995647 is a prime.

It is a super-2 number, since 2×1331131030120312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133113103011988 and 133113103012006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133113103012037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556551506015 + 66556551506016.

It is an arithmetic number, because the mean of its divisors is an integer number (66556551506016).

Almost surely, 2133113103012031 is an apocalyptic number.

133113103012031 is a deficient number, since it is larger than the sum of its proper divisors (1).

133113103012031 is an equidigital number, since it uses as much as digits as its factorization.

133113103012031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 133113103012031 its reverse (130210301311331), we get a palindrome (263323404323362).

The spelling of 133113103012031 in words is "one hundred thirty-three trillion, one hundred thirteen billion, one hundred three million, twelve thousand, thirty-one".