Base | Representation |
---|---|
bin | 11110010001000011011100… |
… | …111011111000001110110101 |
3 | 122110022111210001112200100222 |
4 | 132101003130323320032311 |
5 | 114421412101234400343 |
6 | 1151035230535344125 |
7 | 40016056325462021 |
oct | 3621033473701665 |
9 | 573274701480328 |
10 | 133113333121973 |
11 | 39461058320976 |
12 | 12b1a309b22045 |
13 | 59376c1cc02b9 |
14 | 24c2a10bd7381 |
15 | 105c8b382ba68 |
hex | 7910dcef83b5 |
133113333121973 has 2 divisors, whose sum is σ = 133113333121974. Its totient is φ = 133113333121972.
The previous prime is 133113333121919. The next prime is 133113333121997. The reversal of 133113333121973 is 379121333311331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119987443238884 + 13125889883089 = 10953878^2 + 3622967^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133113333121973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133113333121673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556666560986 + 66556666560987.
It is an arithmetic number, because the mean of its divisors is an integer number (66556666560987).
Almost surely, 2133113333121973 is an apocalyptic number.
It is an amenable number.
133113333121973 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113333121973 is an equidigital number, since it uses as much as digits as its factorization.
133113333121973 is an evil number, because the sum of its binary digits is even.
The product of its digits is 275562, while the sum is 44.
The spelling of 133113333121973 in words is "one hundred thirty-three trillion, one hundred thirteen billion, three hundred thirty-three million, one hundred twenty-one thousand, nine hundred seventy-three".
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