Base | Representation |
---|---|
bin | 1100000110110100110111… |
… | …1110111101010101101111 |
3 | 1202010120002012010020011101 |
4 | 3001231031332331111233 |
5 | 3221043232433000421 |
6 | 44151102300303531 |
7 | 2542501125051301 |
oct | 301551576752557 |
9 | 52116065106141 |
10 | 13311412000111 |
11 | 427237a056645 |
12 | 15aba10b41ba7 |
13 | 757350b94cc4 |
14 | 3403c0a43971 |
15 | 1813d8b69191 |
hex | c1b4dfbd56f |
13311412000111 has 2 divisors, whose sum is σ = 13311412000112. Its totient is φ = 13311412000110.
The previous prime is 13311411999983. The next prime is 13311412000123. The reversal of 13311412000111 is 11100021411331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311412000111 - 27 = 13311411999983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13311412000181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655706000055 + 6655706000056.
It is an arithmetic number, because the mean of its divisors is an integer number (6655706000056).
Almost surely, 213311412000111 is an apocalyptic number.
13311412000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311412000111 is an equidigital number, since it uses as much as digits as its factorization.
13311412000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 13311412000111 its reverse (11100021411331), we get a palindrome (24411433411442).
The spelling of 13311412000111 in words is "thirteen trillion, three hundred eleven billion, four hundred twelve million, one hundred eleven", and thus it is an aban number.
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