Base | Representation |
---|---|
bin | 1100000110110100110111… |
… | …1111000101011010110001 |
3 | 1202010120002012011220112221 |
4 | 3001231031333011122301 |
5 | 3221043232440030301 |
6 | 44151102301121041 |
7 | 2542501125246622 |
oct | 301551577053261 |
9 | 52116065156487 |
10 | 13311412033201 |
11 | 427237a079497 |
12 | 15aba10b59181 |
13 | 757350ba7099 |
14 | 3403c0a51a49 |
15 | 1813d8b73da1 |
hex | c1b4dfc56b1 |
13311412033201 has 2 divisors, whose sum is σ = 13311412033202. Its totient is φ = 13311412033200.
The previous prime is 13311412033147. The next prime is 13311412033223. The reversal of 13311412033201 is 10233021411331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12862982250000 + 448429783201 = 3586500^2 + 669649^2 .
It is an emirp because it is prime and its reverse (10233021411331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13311412033201 - 211 = 13311412031153 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311412013201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655706016600 + 6655706016601.
It is an arithmetic number, because the mean of its divisors is an integer number (6655706016601).
Almost surely, 213311412033201 is an apocalyptic number.
It is an amenable number.
13311412033201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311412033201 is an equidigital number, since it uses as much as digits as its factorization.
13311412033201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13311412033201 its reverse (10233021411331), we get a palindrome (23544433444532).
The spelling of 13311412033201 in words is "thirteen trillion, three hundred eleven billion, four hundred twelve million, thirty-three thousand, two hundred one".
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