13311413120113 has 2 divisors, whose sum is σ = 13311413120114. Its totient is φ = 13311413120112.

The previous prime is 13311413120107. The next prime is 13311413120149. The reversal of 13311413120113 is 31102131411331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13309414314849 + 1998805264 = 3648207^2 + 44708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13311413120113 is a prime.

It is not a weakly prime, because it can be changed into another prime (13311413120513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655706560056 + 6655706560057.

It is an arithmetic number, because the mean of its divisors is an integer number (6655706560057).

Almost surely, 2^{13311413120113} is an apocalyptic number.

It is an amenable number.

13311413120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311413120113 is an equidigital number, since it uses as much as digits as its factorization.

13311413120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 13311413120113 its reverse (31102131411331), we get a palindrome (44413544531444).

The spelling of 13311413120113 in words is "thirteen trillion, three hundred eleven billion, four hundred thirteen million, one hundred twenty thousand, one hundred thirteen".