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13311414044221 is a prime number
BaseRepresentation
bin1100000110110100111000…
…0110110000011000111101
31202010120002022222002011011
43001231032012300120331
53221043233443403341
644151102412155221
72542501151323636
oct301551606603075
952116068862134
1013311414044221
114272380222397
1215aba11768b11
1375735142c537
143403c101688d
151813d8e1eb81
hexc1b4e1b063d

13311414044221 has 2 divisors, whose sum is σ = 13311414044222. Its totient is φ = 13311414044220.

The previous prime is 13311414044207. The next prime is 13311414044233. The reversal of 13311414044221 is 12244041411331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10395072291321 + 2916341752900 = 3224139^2 + 1707730^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311414044221 - 25 = 13311414044189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311414044261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655707022110 + 6655707022111.

It is an arithmetic number, because the mean of its divisors is an integer number (6655707022111).

Almost surely, 213311414044221 is an apocalyptic number.

It is an amenable number.

13311414044221 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311414044221 is an equidigital number, since it uses as much as digits as its factorization.

13311414044221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13311414044221 its reverse (12244041411331), we get a palindrome (25555455455552).

The spelling of 13311414044221 in words is "thirteen trillion, three hundred eleven billion, four hundred fourteen million, forty-four thousand, two hundred twenty-one".