Base | Representation |
---|---|
bin | 11110010001000100001101… |
… | …001110110110000010100100 |
3 | 122110022120212112020001222222 |
4 | 132101010031032312002210 |
5 | 114421420231202300400 |
6 | 1151035443202411512 |
7 | 40016115364643642 |
oct | 3621041516660244 |
9 | 573276775201888 |
10 | 133114143400100 |
11 | 39461433741915 |
12 | 12b1a4b5360b98 |
13 | 59377c0b31505 |
14 | 24c2a8a67a192 |
15 | 105c90ea34185 |
hex | 79110d3b60a4 |
133114143400100 has 36 divisors (see below), whose sum is σ = 288866113510464. Its totient is φ = 53244104856480.
The previous prime is 133114143400037. The next prime is 133114143400159. The reversal of 133114143400100 is 1004341411331.
It is a self number, because there is not a number n which added to its sum of digits gives 133114143400100.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15956432 + ... + 22821831.
It is an arithmetic number, because the mean of its divisors is an integer number (8024058708624).
Almost surely, 2133114143400100 is an apocalyptic number.
133114143400100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133114143400100 is an abundant number, since it is smaller than the sum of its proper divisors (155751970110364).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133114143400100 is a wasteful number, since it uses less digits than its factorization.
133114143400100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38812604 (or 38812597 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 133114143400100 its reverse (1004341411331), we get a palindrome (134118484811431).
The spelling of 133114143400100 in words is "one hundred thirty-three trillion, one hundred fourteen billion, one hundred forty-three million, four hundred thousand, one hundred".
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