Base | Representation |
---|---|
bin | 1100000110110100111010… |
… | …1010100100011011011010 |
3 | 1202010120002222122001022212 |
4 | 3001231032222210123122 |
5 | 3221043243344314120 |
6 | 44151103345315122 |
7 | 2542501324164515 |
oct | 301551652443332 |
9 | 52116088561285 |
10 | 13311423432410 |
11 | 4272385554924 |
12 | 15aba14935aa2 |
13 | 75735336878c |
14 | 3403c237bd7c |
15 | 1813d9b766c5 |
hex | c1b4eaa46da |
13311423432410 has 32 divisors (see below), whose sum is σ = 24266603496960. Its totient is φ = 5256575430912.
The previous prime is 13311423432401. The next prime is 13311423432421. The reversal of 13311423432410 is 1423432411331.
13311423432410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×133114234324103 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6072722 + ... + 7968738.
It is an arithmetic number, because the mean of its divisors is an integer number (758331359280).
Almost surely, 213311423432410 is an apocalyptic number.
13311423432410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13311423432410 is a deficient number, since it is larger than the sum of its proper divisors (10955180064550).
13311423432410 is a wasteful number, since it uses less digits than its factorization.
13311423432410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1904990.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 13311423432410 its reverse (1423432411331), we get a palindrome (14734855843741).
The spelling of 13311423432410 in words is "thirteen trillion, three hundred eleven billion, four hundred twenty-three million, four hundred thirty-two thousand, four hundred ten".
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