Base | Representation |
---|---|
bin | 111101111111001001… |
… | …1000011011011110111 |
3 | 110201121001011022102101 |
4 | 1323332103003123313 |
5 | 4140110022122201 |
6 | 141052525322531 |
7 | 12421503312412 |
oct | 1737623033367 |
9 | 421531138371 |
10 | 133115426551 |
11 | 514aa208218 |
12 | 21970106447 |
13 | c7254713b3 |
14 | 662b15ab79 |
15 | 36e1607d01 |
hex | 1efe4c36f7 |
133115426551 has 2 divisors, whose sum is σ = 133115426552. Its totient is φ = 133115426550.
The previous prime is 133115426533. The next prime is 133115426557. The reversal of 133115426551 is 155624511331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133115426551 - 217 = 133115295479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133115426551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133115426557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66557713275 + 66557713276.
It is an arithmetic number, because the mean of its divisors is an integer number (66557713276).
Almost surely, 2133115426551 is an apocalyptic number.
133115426551 is a deficient number, since it is larger than the sum of its proper divisors (1).
133115426551 is an equidigital number, since it uses as much as digits as its factorization.
133115426551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 37.
Adding to 133115426551 its reverse (155624511331), we get a palindrome (288739937882).
The spelling of 133115426551 in words is "one hundred thirty-three billion, one hundred fifteen million, four hundred twenty-six thousand, five hundred fifty-one".
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