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13312002032599 is a prime number
BaseRepresentation
bin1100000110110111000100…
…1001110000001111010111
31202010121121022100222120111
43001231301021300033113
53221100440010020344
644151241014543451
72542521551204524
oct301556111601727
952117538328514
1013312002032599
1142726521167a6
1215abb56667b87
137574161b0a5a
1434043915414b
15181420868834
hexc1b712703d7

13312002032599 has 2 divisors, whose sum is σ = 13312002032600. Its totient is φ = 13312002032598.

The previous prime is 13312002032573. The next prime is 13312002032611. The reversal of 13312002032599 is 99523020021331.

13312002032599 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (99523020021331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13312002032599 - 227 = 13311867814871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13312002062599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656001016299 + 6656001016300.

It is an arithmetic number, because the mean of its divisors is an integer number (6656001016300).

Almost surely, 213312002032599 is an apocalyptic number.

13312002032599 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312002032599 is an equidigital number, since it uses as much as digits as its factorization.

13312002032599 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 40.

The spelling of 13312002032599 in words is "thirteen trillion, three hundred twelve billion, two million, thirty-two thousand, five hundred ninety-nine".