Base | Representation |
---|---|
bin | 1100000110110111000100… |
… | …1001110000001111010111 |
3 | 1202010121121022100222120111 |
4 | 3001231301021300033113 |
5 | 3221100440010020344 |
6 | 44151241014543451 |
7 | 2542521551204524 |
oct | 301556111601727 |
9 | 52117538328514 |
10 | 13312002032599 |
11 | 42726521167a6 |
12 | 15abb56667b87 |
13 | 7574161b0a5a |
14 | 34043915414b |
15 | 181420868834 |
hex | c1b712703d7 |
13312002032599 has 2 divisors, whose sum is σ = 13312002032600. Its totient is φ = 13312002032598.
The previous prime is 13312002032573. The next prime is 13312002032611. The reversal of 13312002032599 is 99523020021331.
13312002032599 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (99523020021331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13312002032599 - 227 = 13311867814871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312002062599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656001016299 + 6656001016300.
It is an arithmetic number, because the mean of its divisors is an integer number (6656001016300).
Almost surely, 213312002032599 is an apocalyptic number.
13312002032599 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312002032599 is an equidigital number, since it uses as much as digits as its factorization.
13312002032599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 87480, while the sum is 40.
The spelling of 13312002032599 in words is "thirteen trillion, three hundred twelve billion, two million, thirty-two thousand, five hundred ninety-nine".
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