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13312110130000 = 245411443273181
BaseRepresentation
bin1100000110110111011110…
…0110000111001101010000
31202010121212211202220022221
43001231313212013031100
53221101200143130000
644151255435510424
72542524333053353
oct301556746071520
952117784686287
1013312110130000
1142726a81389a0
1215abb868b8414
137574326cb106
1434044965229a
1518142a0bc61a
hexc1b77987350

13312110130000 has 200 divisors, whose sum is σ = 35239442093856. Its totient is φ = 4829822400000.

The previous prime is 13312110129991. The next prime is 13312110130031. The reversal of 13312110130000 is 3101121331.

13312110130000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×133121101300002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 48593410 + ... + 48866590.

Almost surely, 213312110130000 is an apocalyptic number.

13312110130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312110130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17619721046928).

13312110130000 is an abundant number, since it is smaller than the sum of its proper divisors (21927331963856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312110130000 is a wasteful number, since it uses less digits than its factorization.

13312110130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 273663 (or 273642 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13312110130000 its reverse (3101121331), we get a palindrome (13315211251331).

The spelling of 13312110130000 in words is "thirteen trillion, three hundred twelve billion, one hundred ten million, one hundred thirty thousand".