Base | Representation |
---|---|
bin | 11000110010111011… |
… | …01011001011000101 |
3 | 1021100202002022200022 |
4 | 30121131223023011 |
5 | 204230400030201 |
6 | 10040540424525 |
7 | 650613036056 |
oct | 143135531305 |
9 | 37322068608 |
10 | 13312111301 |
11 | 5711381285 |
12 | 26b6248145 |
13 | 1341c50348 |
14 | 903db272d |
15 | 52da5441b |
hex | 31976b2c5 |
13312111301 has 2 divisors, whose sum is σ = 13312111302. Its totient is φ = 13312111300.
The previous prime is 13312111279. The next prime is 13312111387. The reversal of 13312111301 is 10311121331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12594675076 + 717436225 = 112226^2 + 26785^2 .
It is a cyclic number.
It is not a de Polignac number, because 13312111301 - 26 = 13312111237 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13312111301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312111391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656055650 + 6656055651.
It is an arithmetic number, because the mean of its divisors is an integer number (6656055651).
Almost surely, 213312111301 is an apocalyptic number.
It is an amenable number.
13312111301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312111301 is an equidigital number, since it uses as much as digits as its factorization.
13312111301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13312111301 its reverse (10311121331), we get a palindrome (23623232632).
The spelling of 13312111301 in words is "thirteen billion, three hundred twelve million, one hundred eleven thousand, three hundred one".
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