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133121233452523 is a prime number
BaseRepresentation
bin11110010001001010110011…
…110101001111110111101011
3122110100021011122102001111011
4132101022303311033313223
5114422024241230440043
61151043014515044351
740016456156254501
oct3621126365176753
9573307148361434
10133121233452523
1139464441903178
1212b1b9538a06b7
1359383809a71c4
1424c3160158671
15105cbc71da59d
hex7912b3d4fdeb

133121233452523 has 2 divisors, whose sum is σ = 133121233452524. Its totient is φ = 133121233452522.

The previous prime is 133121233452509. The next prime is 133121233452583. The reversal of 133121233452523 is 325254332121331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133121233452523 is a prime.

It is a super-2 number, since 2×1331212334525232 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133121233452503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560616726261 + 66560616726262.

It is an arithmetic number, because the mean of its divisors is an integer number (66560616726262).

Almost surely, 2133121233452523 is an apocalyptic number.

133121233452523 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121233452523 is an equidigital number, since it uses as much as digits as its factorization.

133121233452523 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 388800, while the sum is 40.

Adding to 133121233452523 its reverse (325254332121331), we get a palindrome (458375565573854).

The spelling of 133121233452523 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, two hundred thirty-three million, four hundred fifty-two thousand, five hundred twenty-three".