Search a number
-
+
133121233462519 is a prime number
BaseRepresentation
bin11110010001001010110011…
…110101010010010011110111
3122110100021011122102120012101
4132101022303311102103313
5114422024241231300034
61151043014515202531
740016456156325601
oct3621126365222367
9573307148376171
10133121233462519
113946444190a735
1212b1b9538a6447
1359383809ab913
1424c316015c171
15105cbc71dd514
hex7912b3d524f7

133121233462519 has 2 divisors, whose sum is σ = 133121233462520. Its totient is φ = 133121233462518.

The previous prime is 133121233462447. The next prime is 133121233462579. The reversal of 133121233462519 is 915264332121331.

It is a strong prime.

It is an emirp because it is prime and its reverse (915264332121331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133121233462519 - 217 = 133121233331447 is a prime.

It is a super-2 number, since 2×1331212334625192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133121233462579) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560616731259 + 66560616731260.

It is an arithmetic number, because the mean of its divisors is an integer number (66560616731260).

Almost surely, 2133121233462519 is an apocalyptic number.

133121233462519 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121233462519 is an equidigital number, since it uses as much as digits as its factorization.

133121233462519 is an evil number, because the sum of its binary digits is even.

The product of its digits is 699840, while the sum is 46.

The spelling of 133121233462519 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, two hundred thirty-three million, four hundred sixty-two thousand, five hundred nineteen".