Base | Representation |
---|---|
bin | 11110010001001010110011… |
… | …110101010010110011101011 |
3 | 122110100021011122102122222210 |
4 | 132101022303311102303223 |
5 | 114422024241231331210 |
6 | 1151043014515220203 |
7 | 40016456156334540 |
oct | 3621126365226353 |
9 | 573307148378883 |
10 | 133121233464555 |
11 | 39464441911216 |
12 | 12b1b9538a7663 |
13 | 59383809ac81b |
14 | 24c316015cbc7 |
15 | 105cbc71dde20 |
hex | 7912b3d52ceb |
133121233464555 has 64 divisors (see below), whose sum is σ = 246854221056000. Its totient is φ = 59997314979840.
The previous prime is 133121233464511. The next prime is 133121233464581. The reversal of 133121233464555 is 555464332121331.
It is a happy number.
It is not a de Polignac number, because 133121233464555 - 210 = 133121233463531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 639751171 + ... + 639959219.
It is an arithmetic number, because the mean of its divisors is an integer number (3857097204000).
Almost surely, 2133121233464555 is an apocalyptic number.
133121233464555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133121233464555 is a deficient number, since it is larger than the sum of its proper divisors (113732987591445).
133121233464555 is a wasteful number, since it uses less digits than its factorization.
133121233464555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293964.
The product of its digits is 3888000, while the sum is 48.
Adding to 133121233464555 its reverse (555464332121331), we get a palindrome (688585565585886).
The spelling of 133121233464555 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, two hundred thirty-three million, four hundred sixty-four thousand, five hundred fifty-five".
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