Base | Representation |
---|---|
bin | 11110010001001010110011… |
… | …110101010010110011101010 |
3 | 122110100021011122102122222202 |
4 | 132101022303311102303222 |
5 | 114422024241231331204 |
6 | 1151043014515220202 |
7 | 40016456156334536 |
oct | 3621126365226352 |
9 | 573307148378882 |
10 | 133121233464554 |
11 | 39464441911215 |
12 | 12b1b9538a7662 |
13 | 59383809ac81a |
14 | 24c316015cbc6 |
15 | 105cbc71dde1e |
hex | 7912b3d52cea |
133121233464554 has 32 divisors (see below), whose sum is σ = 204997905979776. Its totient is φ = 64795740065280.
The previous prime is 133121233464511. The next prime is 133121233464581. The reversal of 133121233464554 is 455464332121331.
It is a junction number, because it is equal to n+sod(n) for n = 133121233464499 and 133121233464508.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161139554 + ... + 161963570.
It is an arithmetic number, because the mean of its divisors is an integer number (6406184561868).
Almost surely, 2133121233464554 is an apocalyptic number.
133121233464554 is a deficient number, since it is larger than the sum of its proper divisors (71876672515222).
133121233464554 is a wasteful number, since it uses less digits than its factorization.
133121233464554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 828350.
The product of its digits is 3110400, while the sum is 47.
Adding to 133121233464554 its reverse (455464332121331), we get a palindrome (588585565585885).
The spelling of 133121233464554 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, two hundred thirty-three million, four hundred sixty-four thousand, five hundred fifty-four".
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