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13312131132300 = 2235271113223374007
BaseRepresentation
bin1100000110110111100011…
…0110001110101110001100
31202010121221022021221001220
43001231320312032232030
53221101221032213200
644151301510003340
72542525006425510
oct301557066165614
952117838257056
1013312131132300
114272708a83270
1215abb91946550
13757436b72800
1434044c35c140
1518142bd6a4a0
hexc1b78d8eb8c

13312131132300 has 1728 divisors, whose sum is σ = 55739696431104. Its totient is φ = 2375756697600.

The previous prime is 13312131132253. The next prime is 13312131132317. The reversal of 13312131132300 is 323113121331.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 3322216897 + ... + 3322220903.

It is an arithmetic number, because the mean of its divisors is an integer number (32256768768).

Almost surely, 213312131132300 is an apocalyptic number.

13312131132300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312131132300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27869848215552).

13312131132300 is an abundant number, since it is smaller than the sum of its proper divisors (42427565298804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312131132300 is a wasteful number, since it uses less digits than its factorization.

13312131132300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4128 (or 4108 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 13312131132300 its reverse (323113121331), we get a palindrome (13635244253631).

It can be divided in two parts, 13312131 and 132300, that added together give a palindrome (13444431).

The spelling of 13312131132300 in words is "thirteen trillion, three hundred twelve billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred".