Base | Representation |
---|---|
bin | 10011010111110010011… |
… | …111000101100101010011 |
3 | 11201021002112100202012111 |
4 | 103113302133011211103 |
5 | 133302311030130232 |
6 | 2455314553210151 |
7 | 165114462622522 |
oct | 23276237054523 |
9 | 4637075322174 |
10 | 1331213130067 |
11 | 47362311a857 |
12 | 195bb8700957 |
13 | 986c0900182 |
14 | 48606b804b9 |
15 | 249642d0047 |
hex | 135f27c5953 |
1331213130067 has 2 divisors, whose sum is σ = 1331213130068. Its totient is φ = 1331213130066.
The previous prime is 1331213129989. The next prime is 1331213130077. The reversal of 1331213130067 is 7600313121331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331213130067 - 215 = 1331213097299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331213130077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665606565033 + 665606565034.
It is an arithmetic number, because the mean of its divisors is an integer number (665606565034).
Almost surely, 21331213130067 is an apocalyptic number.
1331213130067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331213130067 is an equidigital number, since it uses as much as digits as its factorization.
1331213130067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 1331213130067 its reverse (7600313121331), we get a palindrome (8931526251398).
The spelling of 1331213130067 in words is "one trillion, three hundred thirty-one billion, two hundred thirteen million, one hundred thirty thousand, sixty-seven".
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