133121401115837 has 2 divisors, whose sum is σ = 133121401115838. Its totient is φ = 133121401115836.

The previous prime is 133121401115783. The next prime is 133121401115887. The reversal of 133121401115837 is 738511104121331.

Together with previous prime (133121401115783) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110716145686276 + 22405255429561 = 10522174^2 + 4733419^2 .

It is a cyclic number.

It is not a de Polignac number, because 133121401115837 - 2³² = 133117106148541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133121401115794 and 133121401115803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133121401115887) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560700557918 + 66560700557919.

It is an arithmetic number, because the mean of its divisors is an integer number (66560700557919).

Almost surely, 2^{133121401115837} is an apocalyptic number.

It is an amenable number.

133121401115837 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121401115837 is an equidigital number, since it uses as much as digits as its factorization.

133121401115837 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 41.

The spelling of 133121401115837 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred one million, one hundred fifteen thousand, eight hundred thirty-seven".