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133121426034049 is a prime number
BaseRepresentation
bin11110010001001010111111…
…010011111000110110000001
3122110100021200001210012200021
4132101022333103320312001
5114422030140031042144
61151043045554453441
740016464015213615
oct3621127723706601
9573307601705607
10133121426034049
1139464530589562
1212b1b9a8294281
1359383b186497b
1424c317b969345
15105cbd907b884
hex7912bf4f8d81

133121426034049 has 2 divisors, whose sum is σ = 133121426034050. Its totient is φ = 133121426034048.

The previous prime is 133121426034011. The next prime is 133121426034127. The reversal of 133121426034049 is 940430624121331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127838751296400 + 5282674737649 = 11306580^2 + 2298407^2 .

It is a cyclic number.

It is not a de Polignac number, because 133121426034049 - 235 = 133087066295681 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133121426033996 and 133121426034014.

It is not a weakly prime, because it can be changed into another prime (133121426031049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560713017024 + 66560713017025.

It is an arithmetic number, because the mean of its divisors is an integer number (66560713017025).

Almost surely, 2133121426034049 is an apocalyptic number.

It is an amenable number.

133121426034049 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121426034049 is an equidigital number, since it uses as much as digits as its factorization.

133121426034049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 43.

The spelling of 133121426034049 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred twenty-six million, thirty-four thousand, forty-nine".