Base | Representation |
---|---|
bin | 11110010001001011100001… |
… | …101010001010110110100011 |
3 | 122110100100011020010120101121 |
4 | 132101023201222022312203 |
5 | 114422032330042102243 |
6 | 1151043223102113111 |
7 | 40016514213333331 |
oct | 3621134152126643 |
9 | 573310136116347 |
10 | 133122002300323 |
11 | 394647a68a6983 |
12 | 12b1bb2927b797 |
13 | 593847407082a |
14 | 24c31d42d4b51 |
15 | 105cc1e95c1ed |
hex | 7912e1a8ada3 |
133122002300323 has 2 divisors, whose sum is σ = 133122002300324. Its totient is φ = 133122002300322.
The previous prime is 133122002300291. The next prime is 133122002300429. The reversal of 133122002300323 is 323003200221331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133122002300323 - 25 = 133122002300291 is a prime.
It is not a weakly prime, because it can be changed into another prime (133122002309323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561001150161 + 66561001150162.
It is an arithmetic number, because the mean of its divisors is an integer number (66561001150162).
Almost surely, 2133122002300323 is an apocalyptic number.
133122002300323 is a deficient number, since it is larger than the sum of its proper divisors (1).
133122002300323 is an equidigital number, since it uses as much as digits as its factorization.
133122002300323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 133122002300323 its reverse (323003200221331), we get a palindrome (456125202521654).
The spelling of 133122002300323 in words is "one hundred thirty-three trillion, one hundred twenty-two billion, two million, three hundred thousand, three hundred twenty-three".
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