Base | Representation |
---|---|
bin | 1100000110110111110110… |
… | …0111110010110101011111 |
3 | 1202010122010220000112010211 |
4 | 3001231331213302311133 |
5 | 3221101402033443033 |
6 | 44151313450513251 |
7 | 2542530001324543 |
oct | 301557547626537 |
9 | 52118126015124 |
10 | 13312211234143 |
11 | 427274a213a38 |
12 | 15abbb4735827 |
13 | 75744a63a353 |
14 | 340458c4da23 |
15 | 181433dde2cd |
hex | c1b7d9f2d5f |
13312211234143 has 2 divisors, whose sum is σ = 13312211234144. Its totient is φ = 13312211234142.
The previous prime is 13312211234099. The next prime is 13312211234263. The reversal of 13312211234143 is 34143211221331.
It is a weak prime.
It is an emirp because it is prime and its reverse (34143211221331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13312211234143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312211232143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656105617071 + 6656105617072.
It is an arithmetic number, because the mean of its divisors is an integer number (6656105617072).
Almost surely, 213312211234143 is an apocalyptic number.
13312211234143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312211234143 is an equidigital number, since it uses as much as digits as its factorization.
13312211234143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 31.
Adding to 13312211234143 its reverse (34143211221331), we get a palindrome (47455422455474).
The spelling of 13312211234143 in words is "thirteen trillion, three hundred twelve billion, two hundred eleven million, two hundred thirty-four thousand, one hundred forty-three".
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