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133122242221332 = 223713121906815221
BaseRepresentation
bin11110010001001011101111…
…111101011001010100010100
3122110100100202221120211010220
4132101023233331121110110
5114422033323002040312
61151043302552314340
740016523155536440
oct3621135775312424
9573310687524126
10133122242221332
113946490a276101
1212b1bb956a29b0
1359384b1994720
1424c3218109820
15105cc35a4ec8c
hex7912eff59514

133122242221332 has 48 divisors (see below), whose sum is σ = 382299772536192. Its totient is φ = 35109162783360.

The previous prime is 133122242221289. The next prime is 133122242221333. The reversal of 133122242221332 is 233122242221331.

133122242221332 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 133122242221293 and 133122242221302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133122242221333) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60953406519 + ... + 60953408702.

It is an arithmetic number, because the mean of its divisors is an integer number (7964578594504).

Almost surely, 2133122242221332 is an apocalyptic number.

133122242221332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

133122242221332 is an abundant number, since it is smaller than the sum of its proper divisors (249177530314860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133122242221332 is a wasteful number, since it uses less digits than its factorization.

133122242221332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121906815248 (or 121906815246 counting only the distinct ones).

The product of its digits is 41472, while the sum is 33.

Adding to 133122242221332 its reverse (233122242221331), we get a palindrome (366244484442663).

Subtracting 133122242221332 from its reverse (233122242221331), we obtain a palindrome (99999999999999).

The spelling of 133122242221332 in words is "one hundred thirty-three trillion, one hundred twenty-two billion, two hundred forty-two million, two hundred twenty-one thousand, three hundred thirty-two".

Divisors: 1 2 3 4 6 7 12 13 14 21 26 28 39 42 52 78 84 91 156 182 273 364 546 1092 121906815221 243813630442 365720445663 487627260884 731440891326 853347706547 1462881782652 1584788597873 1706695413094 2560043119641 3169577195746 3413390826188 4754365793619 5120086239282 6339154391492 9508731587238 10240172478564 11093520185111 19017463174476 22187040370222 33280560555333 44374080740444 66561121110666 133122242221332