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13312243311442 = 2232511152974477
BaseRepresentation
bin1100000110110111111110…
…0010001010001101010010
31202010122020010101012220221
43001231333202022031102
53221101433241431232
644151320554223254
72542530541064425
oct301557742121522
952118203335827
1013312243311442
1142727663330a9
1215b0003424b2a
1375745418b9ba
1434045d1dd9bc
15181436b28897
hexc1b7f88a352

13312243311442 has 16 divisors (see below), whose sum is σ = 20919568928832. Its totient is φ = 6341359618000.

The previous prime is 13312243311413. The next prime is 13312243311463. The reversal of 13312243311442 is 24411334221331.

It is a happy number.

13312243311442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13312243311398 and 13312243311407.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 576475693 + ... + 576498784.

It is an arithmetic number, because the mean of its divisors is an integer number (1307473058052).

Almost surely, 213312243311442 is an apocalyptic number.

13312243311442 is a deficient number, since it is larger than the sum of its proper divisors (7607325617390).

13312243311442 is a wasteful number, since it uses less digits than its factorization.

13312243311442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1152974753.

The product of its digits is 41472, while the sum is 34.

Adding to 13312243311442 its reverse (24411334221331), we get a palindrome (37723577532773).

The spelling of 13312243311442 in words is "thirteen trillion, three hundred twelve billion, two hundred forty-three million, three hundred eleven thousand, four hundred forty-two".

Divisors: 1 2 23 46 251 502 5773 11546 1152974477 2305948954 26518412971 53036825942 289396593727 578793187454 6656121655721 13312243311442