Base | Representation |
---|---|
bin | 11110010001001100100010… |
… | …111101101100000010101111 |
3 | 122110100102222120202122001111 |
4 | 132101030202331230002233 |
5 | 114422042101032423142 |
6 | 1151043523521252451 |
7 | 40016553316151512 |
oct | 3621144275540257 |
9 | 573312876678044 |
10 | 133123097936047 |
11 | 3946520930024a |
12 | 12b20194194127 |
13 | 59385ba053bab |
14 | 24c3299a18d79 |
15 | 105cc85c2ee17 |
hex | 791322f6c0af |
133123097936047 has 2 divisors, whose sum is σ = 133123097936048. Its totient is φ = 133123097936046.
The previous prime is 133123097935967. The next prime is 133123097936053. The reversal of 133123097936047 is 740639790321331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133123097936047 - 211 = 133123097933999 is a prime.
It is a super-2 number, since 2×1331230979360472 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133123097935982 and 133123097936000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133123097936447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561548968023 + 66561548968024.
It is an arithmetic number, because the mean of its divisors is an integer number (66561548968024).
Almost surely, 2133123097936047 is an apocalyptic number.
133123097936047 is a deficient number, since it is larger than the sum of its proper divisors (1).
133123097936047 is an equidigital number, since it uses as much as digits as its factorization.
133123097936047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15431472, while the sum is 58.
The spelling of 133123097936047 in words is "one hundred thirty-three trillion, one hundred twenty-three billion, ninety-seven million, nine hundred thirty-six thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •