Base | Representation |
---|---|
bin | 11110010001001100100011… |
… | …000101001100000001101011 |
3 | 122110100102222201110111220202 |
4 | 132101030203011030001223 |
5 | 114422042102033331214 |
6 | 1151043524031342415 |
7 | 40016553341650361 |
oct | 3621144305140153 |
9 | 573312881414822 |
10 | 133123099902059 |
11 | 3946520a423353 |
12 | 12b20194981a0b |
13 | 59385ba591a07 |
14 | 24c3299dab631 |
15 | 105cc85ebc6de |
hex | 79132314c06b |
133123099902059 has 2 divisors, whose sum is σ = 133123099902060. Its totient is φ = 133123099902058.
The previous prime is 133123099902053. The next prime is 133123099902119. The reversal of 133123099902059 is 950209990321331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133123099902059 - 244 = 115530913857643 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 133123099901995 and 133123099902013.
It is not a weakly prime, because it can be changed into another prime (133123099902053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561549951029 + 66561549951030.
It is an arithmetic number, because the mean of its divisors is an integer number (66561549951030).
Almost surely, 2133123099902059 is an apocalyptic number.
133123099902059 is a deficient number, since it is larger than the sum of its proper divisors (1).
133123099902059 is an equidigital number, since it uses as much as digits as its factorization.
133123099902059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3542940, while the sum is 56.
The spelling of 133123099902059 in words is "one hundred thirty-three trillion, one hundred twenty-three billion, ninety-nine million, nine hundred two thousand, fifty-nine".
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