Base | Representation |
---|---|
bin | 11110010001001100101010… |
… | …000000111001000000111111 |
3 | 122110100110021211022212211012 |
4 | 132101030222000321000333 |
5 | 114422042321322404002 |
6 | 1151043543344345435 |
7 | 40016556253420424 |
oct | 3621145200710077 |
9 | 573313254285735 |
10 | 133123216216127 |
11 | 3946526a047885 |
12 | 12b2020791527b |
13 | 59386086c7cc7 |
14 | 24c32ab607d4b |
15 | 105cc912e5d52 |
hex | 79132a03903f |
133123216216127 has 2 divisors, whose sum is σ = 133123216216128. Its totient is φ = 133123216216126.
The previous prime is 133123216216091. The next prime is 133123216216141. The reversal of 133123216216127 is 721612612321331.
It is a strong prime.
It is an emirp because it is prime and its reverse (721612612321331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133123216216127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133123216216187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561608108063 + 66561608108064.
It is an arithmetic number, because the mean of its divisors is an integer number (66561608108064).
Almost surely, 2133123216216127 is an apocalyptic number.
133123216216127 is a deficient number, since it is larger than the sum of its proper divisors (1).
133123216216127 is an equidigital number, since it uses as much as digits as its factorization.
133123216216127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108864, while the sum is 41.
Adding to 133123216216127 its reverse (721612612321331), we get a palindrome (854735828537458).
The spelling of 133123216216127 in words is "one hundred thirty-three trillion, one hundred twenty-three billion, two hundred sixteen million, two hundred sixteen thousand, one hundred twenty-seven".
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