Base | Representation |
---|---|
bin | 10011010111110011100… |
… | …111111101011010011001 |
3 | 11201021010212022021122201 |
4 | 103113303213331122121 |
5 | 133302330422424423 |
6 | 2455320514450201 |
7 | 165115114164526 |
oct | 23276347753231 |
9 | 4637125267581 |
10 | 1331232233113 |
11 | 4736329881a2 |
12 | 196002b93961 |
13 | 986c485b253 |
14 | 4860951414d |
15 | 24965d052ad |
hex | 135f39fd699 |
1331232233113 has 2 divisors, whose sum is σ = 1331232233114. Its totient is φ = 1331232233112.
The previous prime is 1331232233047. The next prime is 1331232233129. The reversal of 1331232233113 is 3113322321331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1320081506704 + 11150726409 = 1148948^2 + 105597^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331232233113 - 213 = 1331232224921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331232233183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665616116556 + 665616116557.
It is an arithmetic number, because the mean of its divisors is an integer number (665616116557).
Almost surely, 21331232233113 is an apocalyptic number.
It is an amenable number.
1331232233113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331232233113 is an equidigital number, since it uses as much as digits as its factorization.
1331232233113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832, while the sum is 28.
Adding to 1331232233113 its reverse (3113322321331), we get a palindrome (4444554554444).
The spelling of 1331232233113 in words is "one trillion, three hundred thirty-one billion, two hundred thirty-two million, two hundred thirty-three thousand, one hundred thirteen".
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